y^(3/2)=6y

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Solution for y^(3/2)=6y equation:


D( y )

y < 0

y < 0

y in <0:+oo)

y^(3/2) = 6*y // - 6*y

y^(3/2)-(6*y) = 0

y^(3/2)-6*y = 0

y^(3/2)-6*y = 0

y*(y^(1/2)-6) = 0

1*y^(1/2) = 6 // : 1

y^(1/2) = 6

y^(1/2) = 6 // ^ 2

y = 36

y = 0

y = 0

y in { 36, 0 }

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